OK. Check. I am able to identify resistors that are in series and in parallel, and for both of these kinds of hook-ups, I am able to calculate their equivalent resistances. I am primed, pressurized, hydrated, hydraulically lifted, and ready to go. Lay it on me ! Start the countdown.

What's the question ?

**Answer:**

Kinetic energy

**Explanation:**

Since kinetic energy is the energy an object has when it is moving, the answer is kinetic energy :)

**Answer:**

v = 80.62 km/h

**Explanation:**

Given that,

An airplane normally flying at 80 km/h north encounters a wind from the west of 10km/h at right angle to its forward motion a crosswind.

We need to find the resultant velocity of the airplane. It can be calculated as follows :

So, the required velocity is 80.62 km/h.

Sedimentary rock I believe

**Answer:**

Answered

**Explanation:**

W = ∫ F dx = ∫ P dV = ∫ PA dx = PA* H = P∆V

∆V = W/P

= 1 kJ / 1200 kPa = 0.0 833 m3

Both cases the height is H = ∆V/A

IN case 1 ( sectional area = 0.01 m^2)

in case 2 (sectional area = 0.03 m^2)