A formula that shows the elements in a compound i their lowest whole number ratio

**Answer: **

**The reaction mixture will contain [A] = 0.1 M and [B] = 1.0 M**

**Explanation:**

**Below is the reaction**

**A(g) → B(g)**

**And the equilibium constant will be explained in terms of [A] and [B]:**

**Keq = 10 = [B]/[A]**

**If the first conditions are that [A] = 1.1 M and [B] = 0.0 M, the conditions at equilibrium is:**

**[A] = 1.1M - x**

**[B] = 0.0M + x**

**Now we rewrite Keq:**

**Keq = 10 = [0.0 +x] / [1.1 -x]**

**at the end we got it for x:**

**10 = [0.0 +x] / [1.1 -x]**

**10 * (1.1-x) = x**

**11 - 10x = x**

**11 = 11x**

**x = 1**

**equilibrium, the concentrations are:**

**[A] = 1.1 M - 1 = 0.1 M**

**[B] = 0.0 M + 1 = 1.0 M**

Answer: 29.93g

Explanation:

Q = 265J

C = 0.385J/g/°C

Δt = 23°C

M =?

Q = MCΔT

M = Q / CΔT = 265 / (0.385x23)

M = 29.93g

**Answer:**

U = 129.053 KJ/m².h

**Explanation:**

overall heat transfer coefficient (U):

U = (<em>m</em>Cp(ToutH2O - TinH2O))/[A((ToutAir - TinH2O)-(TinAir - ToutH2O))/(Ln(ToutAir - TinH2O)/(TinAir - ToutH2O))]

∴ A = 925 m²

H2O:

∴ mass flow H2O (<em>m</em>) = 45500 Kg/h

∴ Cp H2O = 4186 J/Kg°C

∴ Tin = 80°C

∴ Tout = 150°C

Air:

∴ Tin = 350°C

∴ Tout = 175°C

⇒ U = ((45500Kg/h)(4186J/Kg°C)(150-80))/(925m²)[((175-80)-(350-150))Ln((175-80)/(350-150))]

⇒ U = (1.333 E10 J/h)/(925m²)[(-150)Ln(0.475)]

⇒ U = 129052.73 J/m².h = 129.053 KJ/m².h

**Answer:**

The bonds between water molecules are easily broken by the strong ions of ionic compounds