**Answer:**

**Explanation:**

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the combined gas law:

Thus, we solve for the final volume by solving for V2 as follows:

Now, we plug in the variables to obtain the result in milliliters and making sure we have both temperatures in Kelvins:

Regards!

**Answer:**

The answer to your question is: a. pentose

**Explanation:**

**a) a pentose **is a monosaccharide that has 5 carbons in its structure, if we look at the question the chemical formula only has 5 carbons, then this is the right answer.

**b) an oligosaccharide **is a group of 2 or more monosaccharides (till 5 or 6) then, it will have 10 or more carbons, this is not the right answer

**c) a triose **is a monosaccharide that has only three carbons, this is not the right answer.

**d) a hexose **is a monosaccharide that has 6 carbons, of course this answer is wrong.

**e) a polysaccharide **is a group of 6 or more monosaccharides, it will have 20 or more carbons, this answer is wrong.

The answer is (4) 4.0 mol. This is a stoichiometry problem. You start with 2.0 mol of C2H6 and obtain the moles of C by multiplying 2.0 by the mole ratio, in this case 2. 2.0*2=4.0mol.

**Answer: 0.297 moles of calcium carbonate.**

**Solution:**

Number of moles of HCl = moles

According to reaction

Two moles of HCl are reacting with one mole of , then 0.6 moles of HCl will react with:

=

Moles of calcium carbonate reacted = 0.3 moles

In 0.3 moles of calcium carbonate 10% impurities is present i.e.

of impurity.

**Actual number of moles of calcium carbonate reacted = 0.3 - 0.003 = 0.297 moles.**

**0.833 g/mL**

Density = mass/volume = (1250 g)/(1500 mL) = **0.833 g/mL**